18x^2=96x-128

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Solution for 18x^2=96x-128 equation: 



18x^2=96x-128

We move all terms to the left:

18x^2-(96x-128)=0

We get rid of parentheses

18x^2-96x+128=0

a = 18; b = -96; c = +128;
Δ = b2-4ac
Δ = -962-4·18·128
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{96}{36}=2+2/3$

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